# SOLUTION: A rectangle has an area of 34cm. It's length 5 more than twice it's width

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Question 553911: A rectangle has an area of 34cm. It's length 5 more than twice it's width
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A rectangle has an area of 34cm. It's length 5 more than twice it's width
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Area = L*W = 34
L = 2W + 5
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W*(2W+5) = 34

 Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) Quadratic equation (in our case ) has the following solutons: For these solutions to exist, the discriminant should not be a negative number. First, we need to compute the discriminant : . Discriminant d=161 is greater than zero. That means that there are two solutions: . Quadratic expression can be factored: Again, the answer is: 3.84428877022476, -8.84428877022476. Here's your graph:

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W =~ 3.844
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PS it's = it is