SOLUTION: rectangle's length is 5 ft more than its width. if the width is not changed & the length is increased by 3ft, the new area will be 128 ft^2. What are the dimensions of the original

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Question 552083: rectangle's length is 5 ft more than its width. if the width is not changed & the length is increased by 3ft, the new area will be 128 ft^2. What are the dimensions of the original rectangle?
Answer by JBarnum(2146)   (Show Source): You can put this solution on YOUR website!
l=5+w
w=1-5
2nd rectangle dimensions: 16x8



13-5=8

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=576 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 13, -11. Here's your graph:
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