# SOLUTION: The length of a rectangle is 4 times the width. The perimeter is 50 cm. Find the length and width. Can you show me how to do this, maybe by elimination?

Algebra ->  Algebra  -> Rectangles -> SOLUTION: The length of a rectangle is 4 times the width. The perimeter is 50 cm. Find the length and width. Can you show me how to do this, maybe by elimination?      Log On

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 Click here to see ALL problems on Rectangles Question 550285: The length of a rectangle is 4 times the width. The perimeter is 50 cm. Find the length and width. Can you show me how to do this, maybe by elimination?Answer by TutorDelphia(193)   (Show Source): You can put this solution on YOUR website!l=4w 2l+2w=50 (this is from the perimeter formula 2l+2w=p You mentioned you wanted to do this using the elimination method. Let's get both equations in good form for that. l=4w subtract 4w from both sides l-4w=0 2l+2w=50 divide both sides by 2 l+w=25 minus l-4w=0 5w=25 (minus -4w gives us +4w) w=5 l=20