SOLUTION: The length of a room is 4 less than twice its width. What are the dimensions of the room if the perimeter is 58 feet?
Algebra.Com
Question 547289: The length of a room is 4 less than twice its width. What are the dimensions of the room if the perimeter is 58 feet?
Answer by mathie123(224) (Show Source): You can put this solution on YOUR website!
Let l be the length of the room and w be the width of the room.
From the question we can get two equations :
(1)
and
(2) (this is the formula for perimeter of a rectangle)
Substituing (1) into (2) we get:
Now substituting this value for w into (1) we get:
Therefore the room is 18 by 11.
Hopefully this helps, let me know if you still are not sure.
RELATED QUESTIONS
The length of a room is 4 feet less than twice its width. The perimeter of the room is 58 (answered by checkley79)
The length of a rectangular room is 6 feet longer than twice the width. If the room's... (answered by Solver92311)
a rectangular room has an area of 665 square feet. Its length is three less than twice... (answered by drj)
The length of a rectangular room is 8 feet longer than twice its width. If the room's... (answered by josgarithmetic)
Solve.
The length of a rectangular room is 4 feet longer than twice the width. If the... (answered by doukungfoo)
The length of a rectangular room is 4 feet longer than twice the width. If the room's... (answered by algebrahouse.com)
the length of a rectangle room is 4 feet longer than twice teh width. If the room's... (answered by rfer)
. The length of a rectangular room is 7 feet longer than its width. The area of the room (answered by checkley77)
Please help me solve this equation:
The length of a rectangular room is 3 feet less... (answered by checkley77)