SOLUTION: My problem is I cannot find the answer to this geometry problem The perimeter of a rectangle is 28mm. The length of the rectangle is 4mm less than twice the width. Find the length

Question 534065: My problem is I cannot find the answer to this geometry problem
The perimeter of a rectangle is 28mm. The length of the rectangle is 4mm less than twice the width. Find the length of the rectangle.
I came up with this
P=2L+2W
28=2(2W-4)+2W
28=4W-8+2W
28=6W-8

Can you atlest tell me if I am on the right tract? I am unsure of myself.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 28mm. The length of the rectangle is 4mm less than twice the width. Find the length of the rectangle.
I came up with this
Let width be "w"
The length is 2w-4
------------------------
P = 2L+2W
28 = 2(2w-4)+ 2w
---
14 = 2w-4 + w
3w = 18
width = 6 mm
length = 2w-4 = 2*6-4 = 8 mm
=============================
Cheers,
Stan H.

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