# SOLUTION: I need to know how this answer derived: I figured it out, but I do not know how I figured it out. 76=2(11) + 2(11) +5 The length of a rectangle is 5 in more than twice the width

Algebra ->  Algebra  -> Rectangles -> SOLUTION: I need to know how this answer derived: I figured it out, but I do not know how I figured it out. 76=2(11) + 2(11) +5 The length of a rectangle is 5 in more than twice the width      Log On

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 Geometry: Rectangles Solvers Lessons Answers archive Quiz In Depth

 Question 530942: I need to know how this answer derived: I figured it out, but I do not know how I figured it out. 76=2(11) + 2(11) +5 The length of a rectangle is 5 in more than twice the width. If the perimeter of the rectangle is 76 in, what are the dimensions of the rectangle?Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!L = 2W + 5 . P = 2(L+W) = 76 L+W = 38 so L = 38-W . L = L so 2W + 5 = 38-W . 3W = 33 . W = 11 . L = 2W + 5 L = 2(11) + 5 L = 27 . Check the perimeter P = 2(27+11) = 2*38 = 76 Correct. . Answer: The rectangle has length = 27 inches and width = 11 inches. . Done.