SOLUTION: : the length of a rectangle is 8 cm more than 3 times its width. the perimeter of the rectange is 64 cm. what are the dimension of the rectangle . show work. what is the area of th

Question 530879: : the length of a rectangle is 8 cm more than 3 times its width. the perimeter of the rectange is 64 cm. what are the dimension of the rectangle . show work. what is the area of the rectangle . show work?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
L = 3*W + 8
.
2(L+W) = 64
L+W = 32
so
L = 32-W
.
L = L
so
3W+8 = 32-W
4W = 24
W = 6 cm
.
L = 3W + 8 = 18+8 = 26 cm
.
Check the perimeter.
2(L+W) = 64 ??
2(26+6) = 2*32 = 64
Correct.
.
Re-read the question to make sure you answer it.
In this case, it is asking for the area, not the length and width.
.
Area = L * W
Area = 26 * 6 = 156 cm^2
.
Done.

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