SOLUTION: the length of a badminton court is 4m more than twice its width. if the area of the court is 79.2 m, find its dimensions to the nearest meter. *step by step working thank for

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Question 528008: the length of a badminton court is 4m more than twice its width. if the area of the court is 79.2 m, find its dimensions to the nearest meter.
*step by step working
thank for your cooperation
Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!
Area of the Court = A = 79.2 square meter
Length = L = W +4 m
Width = ?
Length = ?
Area of rectangle = Length * Width
A=L*W
79.2 = (W+4)W
79.2=w^2+4W
w^2+4W-79.2=0
Solve for 'w'
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=332.8 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 7.1214034007931, -11.1214034007931. Here's your graph:


w=7.121 or w=-11.121 (inadmissible)
So w = 7.12
Length = L = W +4 = 7.12+4
Length = L = W +4 = 11.12 meter

Dimension of the Court
=====================
Length = 11.12meter
Width = 7.12meter
Area = 79.2 square meter


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