SOLUTION: I'm trying to set this problem up The lenghth of a rectangle is six cm more than one and one-half times the width.The perimeter of the rectangle if fifty-six cm.find the dimensi

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Question 522401: I'm trying to set this problem up
The lenghth of a rectangle is six cm more than one and one-half times the width.The perimeter of the rectangle if fifty-six cm.find the dimensions.
I put l=6+1and1/2
56=2w+2l
I don't think that's right though
Found 2 solutions by richwmiller, stanbon:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Second equation is fine.
L=6+(1.5W)
56=2L+2W

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is six cm more than one and one-half times the width.The perimeter of the rectangle if fifty-six cm.find the dimensions.
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Let width be "W":
Then L = (3/2)W + 6
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Perimeter = 2(L + W)
56 = 2((3/2)W+6 + W)
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28 = (5/2)W + 6
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(5/2)W = 22
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Width = (2/5)(22) = 44/5 = 8.8 cm
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Lenght = (3/2)(8.8) + 6 = 19.2 cm
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Cheers,
Stan H.
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