SOLUTION: A RECTANGLE HAS AN AREA OF 18 M2 AMD A PERIMETER OF 18 M. WHAT ARE IT LENGTH AND WIDTH?

Question 518978: A RECTANGLE HAS AN AREA OF 18 M2 AMD A PERIMETER OF 18 M. WHAT ARE IT LENGTH AND WIDTH?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A RECTANGLE HAS AN AREA OF 18 M^2 AMD A PERIMETER OF 18 M. WHAT ARE IT LENGTH AND WIDTH?
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Area = (length)(width) = M^2
Perimeter = 2(length+width) = 18M
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L+W = 9M
L = 9M-W
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Area = (9M-W)W = M^2
9MW-W^2 = M^2
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w^2 -9mw+m^2 = 0
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w = [9m +- sqrt(81m^2-4m^2)]/2
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w = [9m +- sqrt(77m^2)]/2
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w = (9/2)m + m*sqrt(77)/2
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w = [9+sqrt(77)](m/2)
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I'll leave solution of "L" to you.
Cheers,
Stan H.
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