SOLUTION: Suppose that the width of a certain rectangle is 2 inches less than its length. The area is numerically 8 less than twice the perimeter. Find the length and width of the rectangle.

Question 506870: Suppose that the width of a certain rectangle is 2 inches less than its length. The area is numerically 8 less than twice the perimeter. Find the length and width of the rectangle.
Answer by emargo19(101) (Show Source): You can put this solution on YOUR website!
Let w be the width
length= w+2
Area=w(w+2)
Perimeter=2(w)+2(w+2)-8

Next solve using Quadratic Formula.

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