SOLUTION: Suppose that the length of a certain rectangle is 2 meters less than two times its width. The perimeter of the rectangle is 32 meters. Find the length and width of the rectangle

SOLUTION: Suppose that the length of a certain rectangle is 2 meters less than two times its width. The perimeter of the rectangle is 32 meters. Find the length and width of the rectangle

Algebra.Com

Question 491670: Suppose that the length of a certain rectangle is 2 meters less than two times its width. The perimeter of the rectangle is 32 meters. Find the length and width of the rectangle
Answer by cleomenius(959) (Show Source): You can put this solution on YOUR website!
L = 2w - 2
W = W
2(2W - 2) + 2W = 32
4W - 4 + 2W = 32
6W = 36
W = 6
===================================
L = 10 meters
W = 6 meters
2(10) + 2(6) = 32 Meters.
==================================
Cleomenius.

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