SOLUTION: The width of a rectangle is 8 more than the length. The perimeter of the rectangle is 56 in. what is the dimensions and area of the rectangle?

Algebra ->  Algebra  -> Rectangles -> SOLUTION: The width of a rectangle is 8 more than the length. The perimeter of the rectangle is 56 in. what is the dimensions and area of the rectangle?      Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   


Question 482342: The width of a rectangle is 8 more than the length. The perimeter of the rectangle is 56 in. what is the dimensions and area of the rectangle?
Answer by jorel1380(2518) About Me  (Show Source):
You can put this solution on YOUR website!
2(l+8)+2l=56
2l+16+2l=56
4l=40
l=10
w=18
The rectangle is 10" by 18"..