SOLUTION: how do you find the dimensions of a rectangle with the area of 120 square feet and a perimeter of 44 feet

Question 479470: how do you find the dimensions of a rectangle with the area of 120 square feet and a perimeter of 44 feet

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do you find the dimensions of a rectangle with the area of 120 square feet and a perimeter of 44 feet
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Equations:
LW = 120
44 = 2(L+W)
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22 = L+W
L = 22-W
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Substitute for "L" and solve for "W":
(22-W)W = 120
22W-W^2 = 120
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W^2-22W+120 = 0
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Factor:
(W-10)(W-12) = 0
----
If W = 10, L = 12
If W = 12, L = 10
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Cheers,
stan H.
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