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put this solution on YOUR website!The length of a rectangle is 1 cm longer than its width.
LET WIDTH =W
LENGTH=W+1
If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
DIAGONAL^2=L^2+W^2
4^2=(W+1)^2+W^2
W^2+2W+1+W^2=16
2W^2+2W-15=0

=2.28
W=2.28 AND L=3.28
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