SOLUTION: I am having trouble finding the length and width if a certain rectangle has an area of 288 square inches and a perimeter of 9 feet. I changed 9 feet into inches which is 108 in

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Question 472435: I am having trouble finding the length and width if a certain rectangle has an area of 288 square inches and a perimeter of 9 feet.
I changed 9 feet into inches which is 108 inches.
I tried to do guess and check, but it is not really working for me...
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

P(rectangle) = 2L + 2W 

 2L + 2W = 108in

  L + W = 54

    L = (54-W)

  (54-W)W = 288 in^2

  W^2 - 54W + 288 = 0

factoring

  (W -48)(W-6) = 0

  (W -48)= 0

   (W-6) = 0

  rectangle is 6in by 48in  or 48in by 6in 

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
 





The perimeter of a rectangle is given by:











and the area is given by:











Plug in numbers:











which means











Then











But since we have an expression for the length in terms of width that we derived from the Area equation, substitute:











Multiply by 











Put in standard form:











Factor and solve for .  Then calculate 







John



My calculator said it, I believe it, that settles it


The Out Campaign: Scarlet Letter of Atheism


 

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