# SOLUTION: the perimeter of a rectangle is 36 yd. the width is 18 yds less han twice the lenght. find the length and the width of the rectangle

Algebra ->  Algebra  -> Rectangles -> SOLUTION: the perimeter of a rectangle is 36 yd. the width is 18 yds less han twice the lenght. find the length and the width of the rectangle      Log On

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 Geometry: Rectangles Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Rectangles Question 467146: the perimeter of a rectangle is 36 yd. the width is 18 yds less han twice the lenght. find the length and the width of the rectangleAnswer by checkley79(3039)   (Show Source): You can put this solution on YOUR website!P=2L+2W W=2L-18 36=2L+2(2L-18) 36=2L+4L-36 36=6L-36 6L=36+36 6L=72 L=72/6 L=12 ANS. FOR THE LENGTH. W=2*12-18 W=24-18 W=6 ANS. FOR THE WIDTH. PROOF: 36=2*12+2*6 36=24+12 36=36