SOLUTION: The length of a rectangle is longer than its width.
If the perimeter of the rectangle is , find its area.
Algebra.Com
Question 466667: The length of a rectangle is longer than its width.
If the perimeter of the rectangle is , find its area.
Found 2 solutions by richard1234, solver91311:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Missing numbers. I hope you did not copy/paste from some website that renders numbers as images and forget to check what you wrote.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the width. Let 
represent the amount the length exceeds the width. Then 
represents the length, 
. Let 
represent the perimeter and 
represent the area.
The perimeter of a rectangle is given by:
So we can say
\ +\ 2w)
From which we can derive:
Similarly, if we allow the width to be represented as 
, we can derive:
The area of a rectangle is given by:
Substituting:
\left(\frac{P\ +\ 2x}{4}\right))
And simplifying results in:
John
My calculator said it, I believe it, that settles it
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