# SOLUTION: If a rectangle has a total perimeter of 288 feet and the length is 7 times it's width,what are the dimensions?

Algebra ->  Algebra  -> Rectangles -> SOLUTION: If a rectangle has a total perimeter of 288 feet and the length is 7 times it's width,what are the dimensions?      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Geometry: Rectangles Solvers Lessons Answers archive Quiz In Depth

 Question 463997: If a rectangle has a total perimeter of 288 feet and the length is 7 times it's width,what are the dimensions?Answer by algebrahouse.com(1079)   (Show Source): You can put this solution on YOUR website!x = width 7x = length Perimeter of a rectangle is 2(width) + 2(length) 2x + 2(7x) = 288 {perimeter is 2(width) + 2(length)} 2x + 14x = 288 {multiplied 2 by 7x} 16x = 288 {combined like terms} x = 18 {divided both sides by 16} 7x = 126 {substituted 18, in for x, into 7x} width = 18 ft and length = 126 ft For more help like this, ask the house: www.algebrahouse.com