SOLUTION: the perimeter of a rectangle is 14 feet and the area is 12 square ft what is the width
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Question 451846: the perimeter of a rectangle is 14 feet and the area is 12 square ft what is the width
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
the perimeter of a rectangle is 14 feet
2L + 2W = 14
Simplify, divide 2
L + W = 7
L = {7-W)
:
the area is 12 square ft what is the width
L*W = 12
replace L with (7-W), find W
W(7-W) = 12
-W^2 + 7W = 12
0 = W^2 - 7W + 12
Factors to
(W-4)(W-3) = 0
W = 4, then L = 3
or
W = 3, then L = 4
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