SOLUTION: The length of a rectangle is 5yds longer than its width. If the perimeter of the rectangle is 30yds , find its area. I need the answer.

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Question 451227: The length of a rectangle is 5yds longer than its width.
If the perimeter of the rectangle is 30yds , find its area.
I need the answer.
Found 2 solutions by jorel1380, ewatrrr:
Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
2w+2(w+5)=30
4w+10=30
4w=20
w=5yds.
l=10yds..
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,





The length of a rectangle is 5yds  longer than its width. 

Let x and (x+5) represent the width and length respectively

  2x + 2(x+5yd) = 30yds

   4x =  20yds

    x = 5yd, the width the length is 10yd

Area(rectangle) = w*l = 5yd*10yd = 50yd^2 

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