SOLUTION: The length is 5 units more than the width. The perimeter is 9 times times the width. How do you find the length and the width of the rectangle described
Algebra.Com
Question 447323: The length is 5 units more than the width. The perimeter is 9 times times the width. How do you find the length and the width of the rectangle described
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
P=2L+2W
9W=2L+2W
2L=7W
L=W+5
9W=2(W+5)+2W
7W=2W+10
5W=10
W=2
L=7
The length is 7 units, the width is 2 units..
RELATED QUESTIONS
The length is 5 units more than the width. The perimeter is 9 times the width. Find the... (answered by swincher4391)
The length is 5 untis less than 2 times the width. The perimeter is 22 units more than... (answered by jorel1380)
find the length of a rectangle where the length is 5 units more than the width and the... (answered by ewatrrr)
The length is 4 units less than 3 times the width. The perimeter is 22 units more than... (answered by solver91311)
The length is 4 units less than 3 times the width. The perimeter is 22 units more than... (answered by macston)
The length is 12 units more than then the width. perimeter is 7 times the width. find the (answered by solver91311)
The length of a rectangle is 9 feet more than its width. The perimeter is 58 feet. find... (answered by ewatrrr)
Find the length a d the width of the rectangle described.
The length is 12 units more... (answered by MathLover1)
The length is 4 units less than 3 times the width. The perimeter is 22 units more than... (answered by ewatrrr,100601)