SOLUTION: A rectangle is 5 feet longer than twice its width. If the rectangle has a perimeter of 88 feet, what are the dimensions of the rectangle?

Question 444067: A rectangle is 5 feet longer than twice
its width. If the rectangle has a perimeter of 88 feet,
what are the dimensions of the rectangle?
Found 2 solutions by jorel1380, chriswen:
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
2W+2(2W+5)=88
2W+4W+10=88
6W=78
W=13
L=31..
Answer by chriswen(106) (Show Source): You can put this solution on YOUR website!
Let x ft be the width
Let 2x+5 ft be the length
P=2(x+2x+5)
88=2(3x+5)
88=6x+10
6x=88-10
6x=78
x=13
2x+5
=2(13)+5
=26+5
=31
Therefore, the rectangle is 31ft by 13ft.
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