SOLUTION: A garden has an area of 96 yd. Its width is 6 yd. Find its perimeter. How do I do that?

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Question 443876: A garden has an area of 96 yd. Its width is 6 yd. Find its perimeter. How do I do that?
Found 3 solutions by chriswen, ewatrrr, unlockmath:
Answer by chriswen(106)   (Show Source): You can put this solution on YOUR website!
A=l*w
The area is 96yd and the width is 6yd.
96=l*6
96/6=l
l=16
The length of the garden is 16yd.
P=2(l+w)
P=2(16+6)
P=2(22)
P=44
The perimeter of the garden is 44yd.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi



Let x and y represent the width and length respectively

 P = 2*y + 28x

AND  x*y = 96yd^2

    6yd = 96yd^2/y   |Its width is 6 yd.

   y = 96yd^2/6yd = 16yd

 2*y + 2*x = P

  2*16yd + 2*6yd = 44 yd  

Answer by unlockmath(1688)   (Show Source): You can put this solution on YOUR website!
 Hello, 

We know the area of a shape is width times height, right?

We can use that to form this equation (Let x be the height):

6x=96

Divide both sides by 6 to get:

x=16 yds is the height

I'll see if you can figure out the perimeter. 

Make sense?

RJ

www.math-unlock.com

 

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