SOLUTION: The perimeter of a rectangle is 120 cm. The length of the diagonol is 9 cm longer than the width. What are the dimensions of the rectangle? You need to use algebra!

Question 429725: The perimeter of a rectangle is 120 cm. The length of the diagonol is 9 cm longer than the width. What are the dimensions of the rectangle? You need to use algebra!
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Solution:Let x cm the width, then the diagonal is x+9 cm, and the length of rectangle, using Pythagorean theorem will be:
, and

The perimeter of rectangle is:2L+2W=120 => L+W=60 Write the equation:
Solve the equation:
, squaring both sides have:
, set equation to zero.
, solve the quadratic equation.
The roots that satisfy our problem is L=33.75 cm and W=26.34 cm.
Done.

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