SOLUTION: the length of a rectangle is 8cm greater than twice its width.find the dimensions if the area is 42cm square
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Question 422141: the length of a rectangle is 8cm greater than twice its width.find the dimensions if the area is 42cm square
Answer by emargo19(101) (Show Source): You can put this solution on YOUR website!
Let the width be x
Let the length be 2x+8
x(2x+8)=42
2x^2+8x=42
2x^2+8x-42=0
Lets use the quadratic equation to factor the equation
a=2 b=8 c=-42
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