# SOLUTION: b) Length of a rectangle is 3 more than its width. The perimeter of the rectangle is 30. Find the length and width.

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 Click here to see ALL problems on Rectangles Question 421139: b) Length of a rectangle is 3 more than its width. The perimeter of the rectangle is 30. Find the length and width. Found 2 solutions by algebrahouse.com, mananth:Answer by algebrahouse.com(1079)   (Show Source): You can put this solution on YOUR website!"b) Length of a rectangle is 3 more than its width. The perimeter of the rectangle is 30. Find the length and width." x = width x + 3 = length {length is 3 more than width} Perimeter of a rectangle = 2(width) + 2(length} 2x + 2(x + 3) = 30 {perimeter is 2(width) + 2(length)} 2x + 2x + 6 = 30 {used distributive property} 4x + 6 = 30 {combined like terms} 4x = 24 {subtracted 6 from both sides} x = 6 {divided both sides by 4} x + 3 = 9 {substituted 6, in for x, into x + 3} width = 6 and length = 9 www.algebrahouse.com Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!Perimeter = 30 Length =x+3 Width =xcm Perimeter =2((x +3)+x) Perimeter =2(2x+ 3) Perimeter =4x +6 30=4x+6 30-6=4x 24=4x x=6 Width Length =9