SOLUTION: Please help me to solve this equation: the length of a rectangle is equal to one less than twice the width. if the perimer is equal to 70, what are the length and width of the rect

SOLUTION: Please help me to solve this equation: the length of a rectangle is equal to one less than twice the width. if the perimer is equal to 70, what are the length and width of the rect

Algebra.Com

Question 419478: Please help me to solve this equation: the length of a rectangle is equal to one less than twice the width. if the perimer is equal to 70, what are the length and width of the rectangle?
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!

let width = x
so, length = 2x -1

2(x +2x -1) = 70
=> 3x -1 = 35
=> x = 12

length = 23, width = 12

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