SOLUTION: A farmer wants to build a pen with one side attached to his barn. He has 800metres of fencing. What is the max area that the pen can be? p = 2L + W 800 = 2L + W W = 800

SOLUTION: A farmer wants to build a pen with one side attached to his barn. He has 800metres of fencing. What is the max area that the pen can be? p = 2L + W 800 = 2L + W W = 800 - 2L

Question 416512: A farmer wants to build a pen with one side attached to his barn. He has 800metres of fencing. What is the max area that the pen can be?
p = 2L + W
800 = 2L + W
W = 800 - 2L

Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
This is an optimization problem requiring derivatives. You are on the right track.
The next step is to maximize the area

Now take the derivative and set = 0

Solving for L gives L = 200 m
And W = 800 - 2L -> W = 400 m
So the max. area = A = L*W = 200*400 = 80000 m^2
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