SOLUTION: the perimeter of a rectangle is 104m. The length is 7m more than twice the width.how do i get the dimensions
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Question 414207: the perimeter of a rectangle is 104m. The length is 7m more than twice the width.how do i get the dimensions
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"the perimeter of a rectangle is 104m. The length is 7m more than twice the width.how do i get the dimensions"
x = width
2x + 7 = length
Perimeter of a rectangle = (2 x length) + (2 x width)
2x + 2(2x + 7) = 104 {perimeter = 2(length + 2(width)}
2x + 4x + 14 = 104 {used distributive property}
6x + 14 = 104 {combined like terms}
6x = 90 {subtracted 14 from both sides}
x = 15 {divided both sides by 6}
2x + 7 = 37 {substituted 15, in for x, into 2x + 7}
width = 15m and length = 37m
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