SOLUTION: The length of a rectangle is 5 cm longer than twice the width. If the width of the rectangle is 6 cm, find the area of the figure.
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Question 413753: The length of a rectangle is 5 cm longer than twice the width. If the width of the rectangle is 6 cm, find the area of the figure.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"The length of a rectangle is 5 cm longer than twice the width. If the width of the rectangle is 6 cm, find the area of the figure."
x = width
2x + 5 = length {length is 5 more than twice the width}
Area of a rectangle = length x width
= x(2x + 5)
= 6[2(6) + 5] {problem states width is 6}
= 6(12 + 5) {multiplied 2 by 6}
= 6(17) {added 12 and 5}
Area = 102 cm^2 {multiplied}
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