SOLUTION: A rectangle has width w. Its length is 1 more than twice its width. Find the perimeter of the rectangle in terms of w.

Question 412790: A rectangle has width w. Its length is 1 more than twice its width. Find the perimeter of the rectangle in terms of w.

Found 2 solutions by algebrahouse.com, shree840:
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
A rectangle has width w. Its length is 1 more than twice its width. Find the perimeter of the rectangle in terms of w.

w = width
2w + 1 = length {one more than twice width}
Perimeter = (2 x length) + (2 x width)
= 2(2w + 1) + 2w {two times length plus two times width equals perimeter}
= 4w + 2 + 2w {used distributive property}
= 6w + 2 {combined like terms}
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Answer by shree840(260) (Show Source): You can put this solution on YOUR website!
length 2w+1
width w
perimeter is 2l+2w
=2(2w+1)+2w
=4w+2+2w
=6w+2
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