SOLUTION: please help me solve this equation: a rectangle has a perimeter of 80 feet, its length is 8 feet more than the width. What is the length and the width.

Question 410644: please help me solve this equation: a rectangle has a perimeter of 80 feet, its length is 8 feet more than the width. What is the length and the width.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a rectangle has a perimeter of 80 feet, its length is 8 feet more than the width.
What is the length and the width.
:
The perimeter:
2L + 2W = 80
simplify, divide by 2
L + W = 40
:
It says,"its length is 8 feet more than the width"; therefore:
L = W + 8
;
Replace L with (W+8) in the 1st simplified equation
(W+8) + W = 40
2W = 40 - 8
2W = 32
W =
W = 16 ft is the width:
:
I'm going to let you find the length, then check the solutions in the perimeter equation.
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