SOLUTION: what is the perimeter of a rectangle whose length is 4 ft 8 in and whose width is 2 ft 5 in

SOLUTION: what is the perimeter of a rectangle whose length is 4 ft 8 in and whose width is 2 ft 5 in

Algebra.Com

Question 409885: what is the perimeter of a rectangle whose length is 4 ft 8 in and whose width is 2 ft 5 in
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
P = 2L + 2W =
P = 2(4 ft 8 in) + 2(2 ft 5 in) =
P = 8 ft 16 in + 4 ft 10 in =
P = 12 ft 26 in =
P = 14 ft 2 in
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