Hi

the length exceeds the width by 10 

Let x and (x+10in) represent the width and length respectively

Question states***  (Note:  P = 2L + 2W

  2x + 2(x+10in) = 68in

solving for x

   4x + 20in = 68in

      4x = 48in

       x = 12in, the width.  the length is 22in  (12in + 10in

CHECKING our Answer***

  2*12in + 2*22in = 68in 

RELATED QUESTIONS

The perimeter of a rectangle is 68 inches. The length exceeds the width by 28 inches.... (answered by ewatrrr)

perimeter of a rectangle is 112 inches the length exceeds the width by 4 inches find the... (answered by rfer)

The perimeter of a rectangle is 230 inches. The length exceeds the width by 47 inches.... (answered by rdamanik)

The perimeter of a rectangle is 94 inches.  The length exceeds the width by 5 inches.... (answered by Jstrasner)

The perimeter of a rectangle is 104 inches. The length exceeds the width by 14 inches.

 (answered by tm.hodgson)

The perimeter of a rectangle is 36 inches. the length exceeds the width by 4 inches. what  (answered by vksarvepalli)

The perimeter of a rectangle is  108 inches. The length exceeds the width by   8 inches.... (answered by oscargut)


the perimeter of a rectangle is 196 inches. The length exceeds the width by 22 inches.... (answered by meshe43)

the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find  (answered by checkley77)