SOLUTION: The length of a rectangle is 3 more than it's width. If the perimiter is 34, what is the length?
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Question 389747: The length of a rectangle is 3 more than it's width. If the perimiter is 34, what is the length?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Let the width be w and the length be 3+w. The perimeter is 34, so
2(w + (3+w)) = 34. The left-hand side simplifies to 2(3 + 2w) so
2(3 + 2w) = 34
3 + 2w = 17
w = 7, 3+w = 10 --> Length = 10
Checking, 2(7 + 10) = 34
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