SOLUTION: The length of a rectangle is 9 cm more than four times the width. If the perimeter of the rectangle is 58 cm, what are its dimensions?

Question 388831: The length of a rectangle is 9 cm more than four times the width. If the perimeter of the rectangle is 58 cm, what are its dimensions?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 9 cm more than four times the width. If the perimeter of the rectangle is 58 cm, what are its dimensions?
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Let the width be "x":
Then the length is "4x+9"
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Perimeter = 2(length + width)
Solve:
58 = 2(4x+9 + x)
29 = 5x+9
5x = 20
x = 4 cm (width)
4x+9 = 25 cm (length)
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Cheers,
Stan H.
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