SOLUTION: Solve by factoring and using the principle of zero products: 2x^2-11x+15=0 OK I done this before but with the quadratic and square rooting I'm lost I done this much so far Please

Question 384176: Solve by factoring and using the principle of zero products:
2x^2-11x+15=0 OK I done this before but with the quadratic and square rooting I'm lost I done this much so far Please help I'm so lost with this
2(x-2)(x+2)-11+15 then add 11 on both sides which would be 2x2=4 and 15+11 =4 -11+11=0

this is my third sending!! hopefully i get some help
Found 2 solutions by jim_thompson5910, scott8148:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given equation

Factor the left side (note: if you need help with factoring, check out this solver)

Now set each factor equal to zero:
or

or Now solve for x in each case

So our answers are

or

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
you have to FOIL two binomial factors to get 2x^2-11x+15

so the x terms of the binomials multiply to 2x^2 ___ like 2x and x

the constant terms multiply to 15 ___ 3 & 5 , and 1 & 15 are the choices

look at the center (x) term coefficient ___ it is negative
this means that the factors of 15 must be negative ___ -3 & -5 , and -1 & -15

now the "tricky" part ___ the factors of the squared term (2x^2)
are multiplied with the factors of the constant term (15)
to end up with the coefficient of the x term (-11)
you have to mix & match to get the right combination

2x * -3 = -6x
x * -5 = -5x
-5x + -6x = -11x

so the factors are ___ (2x - 5)(x - 3) = 0

2x - 5 = 0 ___ 2x = 5 ___ x = 5/2

x - 3 = 0 ___ x = 3
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