# SOLUTION: the perimeter of a rectangle is 36 yd. The width is 18 yd less than twice the length. find the length and width of the rectangle

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 Question 383262: the perimeter of a rectangle is 36 yd. The width is 18 yd less than twice the length. find the length and width of the rectangleAnswer by mandi08(1)   (Show Source): You can put this solution on YOUR website!Perimeter = 2W + 2L 36 = 2W + 2L We will use L as our variable. L is the length; the width is 18 less than twice the length, therefore (2L - 18). Plug this in to the perimeter equation and you get: 36 = 2(2L-18) + 2(L) 36 = 4L - 36 + 2L 72 = 4L + 2L 72 = 6L L=12 Now we know the length, so we need to figure out the width. The equation to find the width is: W = 2L - 18 W = 2(12) - 18 W = 24 - 18 W = 6