SOLUTION: the perimeter of a rectangle is 36 yd. The width is 18 yd less than twice the length. find the length and width of the rectangle

Algebra.Com
Question 383262: the perimeter of a rectangle is 36 yd. The width is 18 yd less than twice the length. find the length and width of the rectangle
Answer by mandi08(1)   (Show Source): You can put this solution on YOUR website!
Perimeter = 2W + 2L
36 = 2W + 2L
We will use L as our variable.
L is the length; the width is 18 less than twice the length, therefore (2L - 18).
Plug this in to the perimeter equation and you get:
36 = 2(2L-18) + 2(L)
36 = 4L - 36 + 2L
72 = 4L + 2L
72 = 6L
L=12
Now we know the length, so we need to figure out the width. The equation to find the width is:
W = 2L - 18
W = 2(12) - 18
W = 24 - 18
W = 6

RELATED QUESTIONS

the perimeter of a rectangle is 36 yd. the width is 18 yds less han twice the lenght.... (answered by checkley79)
The perimeter of a rectangle 36m. The width is 18 yd less than twice the length. Find... (answered by checkley77)
the perimeter of a rectangular pool is 140 yd. if the length is 20 yd less than twice the (answered by mando271)
If the perimeter of a rectangular courtyard is 36 yd, and the length is 3 yd longer than... (answered by mananth)
The perimeter of a rectangle is 36 yards and the length is 15 yards. What is the... (answered by macston)
The length of a rectangle is 6 yd longer than its width. If the perimeter of the... (answered by CharlesG2)
find the width of a rectangle with a length of 6 yd and a perimeter of 18 yd (answered by richwmiller)
The length of a rectangle is 1 yd more than twice its width, and the area of the... (answered by checkley77)
The length of a rectangle is 3 yd less than twice the width, and the area of the... (answered by Cromlix)