SOLUTION: Area of rectangle is 95 square feet. Length is 6 feet longer than width, find dimesions of the rectangle. Round each dimension to the nearest tenth.

Algebra.Com
Question 381505: Area of rectangle is 95 square feet. Length is 6 feet longer than width, find dimesions of the rectangle. Round each dimension to the nearest tenth.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let x and (x + 6) represent the width and length respectively
Area = l*w
(x + 6)x = 95ft^2
x^2 + 6x - 95 = 0

Tossing out the negative solution
x = 7.2ft, the width to the nearest tenth. Length 13.2ft (7.2ft + 6ft)
RELATED QUESTIONS

A soccer field has an area of 135 square feet. The length is 3 feet longer than the... (answered by jorel1380)
The area of a rectangle is 80 square feet. The length is 2 feet longer than the width.... (answered by oberobic)
The width of a rectangle is 7 feet longer than the length. If the area is 330 square... (answered by london maths tutor)
The length of a rectangle is 3 feet longer than twice the width. If the area is 54 square (answered by TimothyLamb)
The Area of rectangle is 78 square feet. The width is 6 feet. Find the... (answered by nyc_function)
The area of a rectangle is 36 square feet. Find the length and the width of the rectangle (answered by ikleyn)
The perimeter of a ractangle is 48 feet the width is 6 feet less than the length what are (answered by mohanraj04)
A rectangle is 6 feet longer than than it is wide. The area of the rectangle is 315... (answered by Alan3354)
The length of a rectangle storage room is 4 feet longer than its width. If the area of... (answered by SHUgrad05)