SOLUTION: The width of a rectangle is 5 times its length. If the width of the rectangle is doubled, then doubled again, the new perimeter is which percent of the original perimeter?

Question 364453: The width of a rectangle is 5 times its length. If the width of the rectangle is doubled, then doubled again, the new perimeter is which percent of the original perimeter?

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The width of a rectangle is 5 times its length. If the width of the rectangle is doubled, then doubled again, the new perimeter is which percent of the original perimeter?
..
let length be x
width = 5x
perimeter = 2*(L+W)
=2*6x
=12x
..
2*2*5x= 20x
length = x
...
perimeter = 2*(20x+x)
=42x
Ratio = 42x/12x
2.5 *100 = 250 %
...
m.ananth@hotmail.ca
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