# SOLUTION: the length of a rectangle is twice its width. the perimeter is 48in. Find the demension of the rectangle.

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 Question 364347: the length of a rectangle is twice its width. the perimeter is 48in. Find the demension of the rectangle.Answer by Mr.positive(13)   (Show Source): You can put this solution on YOUR website!The length of a rectangle is twice its width. The perimeter is 48 inches. Find the dimensions of the rectangle. The perimeter of a rectangle is the distance around the rectangle. The rectangle has 2 short sides, which will be labeled with w, for width. It also has 2 longer sides, which will be labeled with l, for the length. The Perimeter around the object is therefore 2l + 2w P= 2l + 2w. If the width=x, then length= 2x. Remember that the width= x inches P = 2l + 2w 48 = 2l +2w length= 2x inches P=2l + 2w P= 2(2x) + 2(x) 48 = 4x + 2x; simplifying, you obtain 48 = 6x; solving for x, you obtain 8 = x or, x = 8 w = x = 8 inches l = 2x = 2(8 inches) = 16 inches. mathteacher2010@aol.com