SOLUTION: how do u solve for x if the perimeter of the rectangle is x EX. perimeter is 51 the sides we know are 8x-3 and 2x+11

Question 358954: how do u solve for x if the perimeter of the rectangle is x
EX. perimeter is 51 the sides we know are 8x-3 and 2x+11
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
The formula for perimeter is P=2l+2w ---l is length and w is width. So just plug in what we have:
2(8x-3)+2(2x+11)=51
Expand out to:
16x-6+4x+22=51
Combine like terms:
20x+16=51
Subtract 16 and divide 20 into both sides to get:
x=35/20 or 1 3/4
Make sense?
RJ
www.math-unlock.com
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