SOLUTION: the perimeter of a rectangle is 48 feet.what is the dimensions of the rectangle if the length is 6 feet longer than twice the width?
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Question 356678: the perimeter of a rectangle is 48 feet.what is the dimensions of the rectangle if the length is 6 feet longer than twice the width?
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let x represent the width and (2x+6) be the length. Now we can set up an equation:
2x + 2(2x+6)=48
Expand and combine like terms:
4x+14=48
Subtract 14 and divide by 4 each side to get:
x=4.5
So now we know the width is 4.5 feet and the length is 15 feet.
Make sense?
RJ
www.math-unlock.com
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