SOLUTION: The length of a rectangle is twice its width.
If the perimeter of the rectangle is 54, find its area?
Algebra.Com
Question 350691: The length of a rectangle is twice its width.
If the perimeter of the rectangle is 54, find its area?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=2W
LW=54
2W(W)=54
2W^2=54
W^2=54/2
W^2=27
W=SQRT27
W=5.196 ANS. FOR THE WIDTH.
L=2*5.196=10.392 ANS. FOR THE LENGTH.
PROOF:
10.392*5.196=54
54~54
RELATED QUESTIONS
the length of a rectangle is twice its width. if the perimeter of the rectangle is 54 m,... (answered by lwsshak3)
The length of a rectangle is twice its width.
If the perimeter of the rectangle is 54... (answered by TimothyLamb)
The length of a rectangle is twice its width. If the perimeter of the rectangle is 30cm... (answered by checkley77)
The length of a rectangle is twice its width. If the perimeter of the rectangle is 30ft,... (answered by stanbon)
The length of a rectangle is twice its width.
If the perimeter of the rectangle is 30in... (answered by Fombitz)
The length of a rectangle is twice its breadth. If its perimeter is 54 cm, find its... (answered by checkley77)
the length of a rectangle is twice its width its perimeter is 36 centimeters find the... (answered by mananth)
The length of a rectangle is 3 feet less than twice its width. If the perimeter is 54... (answered by waynest)
The length of a rectangle is twice its width. If the perimeter of a rectangle is 120.... (answered by solver91311)