SOLUTION: A rectangle of has an area of 48 and a perimeter of 32. Find the dimensions of the rectangle.
Algebra.Com
Question 350199: A rectangle of has an area of 48 and a perimeter of 32. Find the dimensions of the rectangle.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Lw=48
2L+2w=32
.
L+w=16
L=16-w
w(16-w)=48
16w-w^2=48
w^2-16w+48=0
(w-12)(w-4)=0
w=4, L=12
.
Ed
RELATED QUESTIONS
A rectangle has an area of 48 square feet and a perimeter of 32 feet. Which of the... (answered by sofiyac)
a rectangle has an area of 48 units squared and a perimeter of 32 units. Find the length... (answered by ewatrrr)
A rectangle has a perimeter of 15.4cm and an area of 14.4cm squared. Find the dimensions... (answered by Greenfinch)
Could you please answer the following. "A rectangle has a perimeter of 38 feet and an... (answered by oberobic)
Find the dimensions of a rectangle that has an area 48 m^2 and a diagonal of length 10... (answered by Earlsdon)
a rectangle has an area of 126 units ^2 and a perimeter of 46 units. Find the... (answered by Alan3354)
a rectangle has an area of 36 inches squared cm2 and a perimeter of 54 cm . find the... (answered by Alan3354,ewatrrr)
A rectangle has an area of 60 square meters and a perimeter of 38 meters. find the... (answered by checkley77)
a rectangle has an area of 132 cm ^2 and a perimeter of 56 cm. find the dimensions of the (answered by josgarithmetic)