SOLUTION: Suppose that the width of a certain rectangle is three-fourths of its length, and the area of that same rectangle is 48 square meters. What is the length and the width of this rect
Algebra.Com
Question 349249: Suppose that the width of a certain rectangle is three-fourths of its length, and the area of that same rectangle is 48 square meters. What is the length and the width of this rectangle?
Found 2 solutions by nyc_function, ewatrrr:
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Length = x
Width = (3/4)x = (3x/4)
Area = 48m^2
Use A = L*W
48 = x(3x/4)
After solving for, we get x = -8 and x = 8.
Disregard x = -8 since length and width are distances and distance is positive.
The length is 8 meters.
The width is (3*8)/4 or 6 meters.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
*Note: l*w = the area of a rectangle.
.
the question states the following to be true:
w = (3/4)*l
.
.
.
Multiply both sides of the equation by (4/3)
l = +-8
plus value is what we can use to represent length.
l = 8cm
w = 6m
.
check you answer
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