SOLUTION: the perimeter of a rectangle is 52 ft. the length of the rectangle is 10 ft longer than the width. find the demesions of the rectangle
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Question 342799: the perimeter of a rectangle is 52 ft. the length of the rectangle is 10 ft longer than the width. find the demesions of the rectangle
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
52=2(w+10)+2w
52=2w+20+2w
52-20=2w+2w
32=4w
w=8
width = 8, length = 18
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