SOLUTION: the perimeter of a rectangle is 70 inches, and the length is 13 less than twice the width. write a system of 2 equation and solve to find the dimension.

Question 338462: the perimeter of a rectangle is 70 inches, and the length is 13 less than twice the width. write a system of 2 equation and solve to find the dimension.
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's have x be one side (length) and y (width) be the other so now we can write 2 equations as:
2x+2y=70
x=2y-13
Are you with me?
Now with the second equation subtract 2y from both sides to get:
x-2y=-13
Now add this to the first to get:
3x=57
Divide by 3 to get:
x=19
Plug 19 into the second equation and we get:
y=16
So now we know the width is 16 inches and the length is 19 inches.
Make sense?
RJ
www.math-unlock.com
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